Write a program to print the area of a rectangle by creating a class named 'Area' having two methods. First method named as 'setDim' takes length and breadth of rectangle as parameters and the second method named as 'getArea' returns the area of the rectangle. Length and breadth of rectangle are entered through keyboard.

C++ program is explained below

Explanation:

#include <iostream>

#include <cmath>

#include <iomanip>

#include <string>

using namespace std;

int main(){

string shape;

double height;

double width;

 double radius;

const double PI = 3.1416;

double length;

cout << "Enter the shape type: (rectangle, circle, cylinder) ";

cin >> shape;

cout << endl;

if (shape == "rectangle"){

 cout << "Enter the length of the rectangle: ";

cin >> length;

cout << endl;

cout << "Enter the width of the rectangle: ";

cin >> width;

cout << endl;

cout << "Perimeter of the rectangle = "<< 2 * (length + width) << endl;

cout << "Area of the rectangle = "<< length * width << endl;

}

else if (shape == "circle"){

 cout << "Enter the radius of the circle: ";

 cin >> radius;

cout << "Area of the circle = "<< PI * pow(radius, 2.0) << endl;

 cout << "Circumference of the circle: "<< 2 * PI * radius << endl;

 cout << endl;

}

else if (shape == "cylinder")

{

cout << "Enter the height of the cylinder: ";

cin >> height;

cout << endl;

cout << "Enter the radius of the base of the cylinder: ";

cin >> radius;

cout << endl;

cout << "Surface area of the cylinder: " << 2 * PI * radius * height + 2 * PI * pow(radius, 2.0)<< endl;

cout << "Volume of the cylinder = "<< PI * pow(radius, 2.0)* height << endl;

}

else

cout << "The program does not handle " << shape << endl;

cout << fixed << showpoint << setprecision(2);

return 0;

}

i think the answer is b.