Write a program that accepts any number of homework scores ranging in value from 0 through 10. Prompt the user for a new value if they enter an alphabetic character. Store the values in array. Calculate the average excluding the lowest and highest scores. Display the average as well as the highest and lowest score that were discarded.

This program is written in C++

Note that the average is calculated without the highest and the least value.

Comments are used for explanatory purpose

See attachment for .cpp file.

Program starts here

#include<iostream>

using namespace std;

int main()

{

int num;

cout<<"Enter Number of Test [0-10]: ";

//cin>>num;

while(!(cin>>num) || num > 10|| num<0)

{

cout << "That was invalid. Enter a valid digit: "<<endl;

cin.clear(); // reset the failed input

cin.ignore(123,'\n');//Discard previous input

}

//Declare scores

int scores[num];

//Accept Input

for(int i =0;i<num;i++)

{

cout<<"Enter Test Score "<<(i+1)<<": ";

cin>>scores[i];

}

           //Determine highest

           int max = scores[0];

           for (int i = 1; i < num; i++)

           {

               if (scores[i] > max)

               {

                   max = scores[i];

               }

           }

           //Determine Lowest

           int least = scores[0];

           for (int i = 1; i < num; i++)

           {

               if (scores[i] < least)

               {

                   least = scores[i];

               }

           }

           int sum = 0;

           //Calculate total

           for(int i =0; i< num;i++)

           {

               sum += scores[i];

           }

           //Subtract highest and least values

           sum = sum - least - max;

           //Calculate average

           double average = sum / (num - 2);

           //Print Average

           cout<<"Average = "<<average<<endl;

           //Print Highest

           cout<<"Highest = "<<max<<endl;

           //Print Lowest

           cout<<"Lowest = "<<least;

return 0;  

}

answer; i believe its compare (b3: b4) ;

2b2t

explanation:

2b2t