I am looking for people who know about hacking, ddos and dox who use linux or basic knowledge of code language

Read the code below. what will the computer print if the input for year_variable is 1700? if year_variable == 1776: print("your answer is correct. the declaration of independence was signed in “year_variable”.") elif year_variable < 1776: compute_variable = 1776 - year_variable. print("add “compute_variable“ years to your answer for the correct answer.") elif year_variable > 1776: compute_variable = year_variable - 1776 print("subtract “compute_variable” years from your answer for the correct answer.")

How do you make a lenny face? plz, brailiest to who can answer first.

Acomputer has a two-level cache. suppose that 60% of the memory references hit on the first level cache, 35% hit on the second level, and 5% miss. the access times are 5 nsec, 15 nsec, and 60 nsec, respectively, where the times for the level 2 cache and memory start counting at the moment it is known that they are needed (e. g., a level 2 cache access does not even start until the level 1 cache miss occurs). what is the average access time?