Print "Censored" if userInput contains the word "darn", else print userInput. End with a newline. Ex: If userInput is "That darn cat.", then output is: Censored Ex: If userInput is "Dang, that was scary!", then output is: Dang, that was scary! Note: If the submitted code has out-of-range access, the system will stop running the code after a few seconds, and report "Program end never reached." The system doesn't print the test case that caused the reported message. #include
#include
using namespace std;
int main() {
string userInput;
getline(cin, userInput);
/* Your solution goes here */
return 0;
}

The program goes as follows

Comments are used to explain difficult lines

#include <iostream>

#include <string>

using namespace std;

int main()

{

string userinput;

getline(cin,userinput);

/* My Solution starts here*/

//Initialize sub string position to 0

int stringpos = 0;

// Declare an iterating variable to iterate through userinput

int startpos;  

//Declare and initialize a determinant variable

int k = 0;

while((startpos = userinput.find("darn",stringpos))!=string::npos)

{

 //If userinput contaings "darn", increase k by 1

k++;

// Go to next string position

stringpos = startpos+1;  

}

//If determinant variable k is p then, userinput does not contain "darn"

if(k==0)

{

 cout<<userinput;

}

//Otherwise, it contains "darn"

else

{

 cout<<"Censored";

}

/* My Solution ends here*/

return 0;

}

See attached for .cpp program file

answer; /// i believe the correct answer is people should evaluate different forms of savings vehicles based on their needs; good luck

the answer is you.