Let a and b be two vector. i. e. a and b are two vectors, of possibly different sizes, containing integers. Further assume that in both a and b the integers are sorted in ascending order.
1. Write a function:
vector merge( vector a, vector b)
that will merge the two vectors into one new one and return the merged vector.
By merge we mean that the resulting vector should have all the elements from a and b, and all its elements should be in ascending order.
For example:
a: 2,4,6,8
b: 1,3,7,10,13
the merge will be: 1,2,3,4,6,7,8,10,13
Do this in two ways. In way 1 you cannot use any sorting function. In way 2 you must.

A  C++ program was used in writing a function in merging ( vector a, vector b)   or that will merge the two vectors into one new one and return the merged vector.

Explanation:

Solution

THE CODE:

#include <iostream>

#include <vector>

using namespace std;

vector<int> merge(vector<int> a, vector<int> b) {

   vector<int> vec;

   int i = 0, j = 0;

   while(i < a.size() || j < b.size()) {

       if(i >= a.size() || (j < b.size() && b[j] < a[i])) {

           if(vec.empty() || vec[vec.size()-1] != b[j])

               vec.push_back(b[j]);

           j++;

       } else {

           if(vec.empty() || vec[vec.size()-1] != a[i])

               vec.push_back(a[i]);

           i++;

       }

   }

   return vec;

}

int main() {

   vector<int> v1 = {2, 4, 6, 8};

   vector<int> v2 = {1, 3, 7, 10, 13};

   vector<int> vec = merge(v1, v2);

   for(int i = 0; i < vec.size(); ++i) {

       cout << vec[i] << " ";

   }

   cout << endl;

   return 0;

}

make sure each item is its own paragraph.