Suppose the following groups are defined to shorten a system’s access control lists: – Group1: Alice, Bob, Cynthia, David, Eve – Group2: Alice, Bob, Cynthia, Eve – Group3: Bob, Cynthia Suppose the access control list for File 1 is: – File 1: Group 1, R; Group 2, RW If Alice wants to write to File 1 giving your reasoning, state whether Alice will be allowed to do so if: i) The first relevant entry policy is applied ii) The any permission in list policy is applied Suppose the access control list for File 2 is: – File 2: Group 3, RWE iii) Show how the need for a Group 3 for File 2 can be removed using access none. iv) Show how you can eliminate the need for a Group 2 for File 1 access.

This problem has been solved! see the answeran evil king has a cellar containing n bottles of expensive wine, and his guards have just caught a spy trying to poison the king’s wine. fortunately, the guards caught the spy after he succeeded in poisoning only one bottle. unfortunately, they don’t know which one. to make matters worse, the poison the spy used was very deadly; just one drop diluted even a billion to one will still kill someone. even so, the poison works slowly; it takes a full month for the person to die. design a scheme that allows the evil king to determine exactly which one of his wine bottles was poisoned in just one month’s time while expending at most o(logn) of his taste testers. you are not allowed to use n testers, one for each bottle, and see which one tester dies after 30 days.(no pseudocode needed. just answer in words, how many testers you use, how you use them and why you correctly identify the poisoned bottle in 30 days)

Anul 2017 tocmai s-a încheiat, suntem trişti deoarece era număr prim, însă avem şi o veste bună, anul 2018 este produs de două numere prime, 2 şi 1009. dorel, un adevărat colecţionar de numere prime, şi-a pus întrebarea: “câte numere dintr-un interval [a, b] se pot scrie ca produs de două numere prime? “.

3. what is the output of the following statements? temporary object1; temporary object2("rectangle", 8.5, 5); temporary object3("circle", 6, 0); temporary object4("cylinder", 6, 3.5); cout < < fixed < < showpoint < < setprecision(2); object1.print(); object2.print(); object3.print(); object4.print(); object1.set("sphere", 4.5, 0); object1.print();