Using the College Registration example from Section 6.7.3 as a starting point, do the following:-Recode the logic sing CMP and conditional jump instructions (instead of the .IF and .ELSEIF directives).-Perform range checking on the credits value; it cannot be less than 1 or greater than 30. If an invalid entry is discovered, display an appropriate error message.-Prompt the user for the grade average and credits values. Display a message that shows the outcome of the evaluation, such as "The student can register" or "The student cannot register".6.7.3 example:.dataTRUE = 1FALSE = 0gradeAverage WORD 275 ; test valuecredits WORD 12 ; test valueOkToRegister BYTE ?.codemain PROCmov OkToRegister, FALSE. IF gradeAverage > 350mov OkToRegister, TRUE. ELSEIF (gradeAverage > 250) && (credits <= 16)mov OkToRegister, TRUE. ELSEIF (credits <= 12)mov OkToRegister, TRUE. ENDIF

State the parts of a variable declaration?

1. ask the user how many questions are in the quiz. 2. ask the user to enter the key (that is, the correct answers). there should be one answer for each question in the quiz, and each answer should be an integer. e. g., 34 7 13 100 81 3 9 10 321 12 might be the key for a 10-question quiz. you will need to store the key in an array. 3. ask the user to enter the answers for the quiz to be graded. there needs to be one answer for each question. note that these answers do not need to be stored; each answer can simply be compared to the key as it is entered. 4. when the user has entered all of the answers to be graded, print the number correct and the percent correct. 5. add a loop so that the user can grade any number of quizzes with a single key. after the results have been printed for each quiz, ask "grade another quiz? (y/n)." note: you only have one array (the key). you are not creating a new key for each set of quiz answers.

Use a software program or a graphing utility with matrix capabilities to solve the system of linear equations using an inverse matrix. x1 + 2x2 − x3 + 3x4 − x5 = 6 x1 − 3x2 + x3 + 2x4 − x5 = −6 2x1 + x2 + x3 − 3x4 + x5 = 3 x1 − x2 + 2x3 + x4 − x5 = −3 2x1 + x2 − x3 + 2x4 + x5 = 5