Computers and Technology, 07.05.2020 04:04, IkweWolf4431

Create a winform application that lets the user enter a temperature. With a ComboBox object offer the user three choices for input type: Farenheit, Celsius, and Kelvin. Offer the same three choices for the output type. Now when the user clicks the Calculate button, convert them temp and show the user the results.

Answers: 3

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Answers

answered: zookieblu

See explaination

Explanation:

//namespace

using System;

using System.Windows.Forms;

//application namespace

namespace TemperatureConversionApp

{

public partial class Form1 : Form

{

public Form1()

{

InitializeComponent();

}

//calculate button click

private void btnCalculate_Click(object sender, EventArgs e)

{

//taking temperature type

string temperatureType = cmbTemperatureType.SelectedItem.ToString();

//taking temperature entered by user

double temperature = double.Parse(txtTemperature.Text);

//taking conversion temperature type

string conversionType = cmbConversionType.SelectedItem.ToString();

//checking temperature type and conversion type

if(temperatureType == "Farenheit" && conversionType == "Celsius")

{

//if Farenheit to Celsius temperature then

double temp = (temperature - 32) * 5 / 9;

//display on the label

lblDetails.Text = temperature.ToString("0.00") + " Farenheit is " + temp.ToString("0.00") + " Celsius";

}

else if (temperatureType == "Farenheit" && conversionType == "Kelvin")

{

//if Farenheit to Kelvin temperature then

double temp = (temperature - 32) * 5 / 9+273.15;

//display on the label

lblDetails.Text = temperature.ToString("0.00") + " Farenheit is " + temp.ToString("0.00") + " Kelvin";

}

else if (temperatureType == "Celsius" && conversionType == "Kelvin")

{

//if Celsius to Kelvin temperature then

double temp = temperature + 273.15;

//display on the label

lblDetails.Text = temperature.ToString("0.00") + " Celsius is " + temp.ToString("0.00") + " Kelvin";

}

else if (temperatureType == "Celsius" && conversionType == "Farenheit")

{

//if Celsius to Farenheit temperature then

double temp = (temperature*9/5) +32;

//display on the label

lblDetails.Text = temperature.ToString("0.00") + " Celsius is " + temp.ToString("0.00") + " Farenheit";

}

else if (temperatureType == "Kelvin" && conversionType == "Farenheit")

{

//if Kelvin to Farenheit temperature then

double temp = (temperature-273.15) * 9 / 5 + 32;

//display on the label

lblDetails.Text = temperature.ToString("0.00") + " Kelvin is " + temp.ToString("0.00") + " Farenheit";

}

else if (temperatureType == "Kelvin" && conversionType == "Celsius")

{

//if Kelvin to Celsius temperature then

double temp = temperature - 273.15;

//display on the label

lblDetails.Text = temperature.ToString("0.00") + " Kelvin is " + temp.ToString("0.00") + " Celsius";

}

else

{

lblDetails.Text = "Select valid temperature conversion unit";

}

//Exit button click

private void btnExit_Click(object sender, EventArgs e)

{

this.Close();//close application

}

check attachment for the windows application

Create a winform application that lets the user enter a temperature. With a ComboBox object offer th

answered: Guest

i would say 3 because windows is the best but vista doesnt do updates anymore

answered: Guest

Idk with yr talking about there's nothing no even a pic so how can ppl u not trying to be rude or anything

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Create a winform application that lets the user enter a temperature. With a ComboBox object offer th...