Given an unlimited supply of coins of denominations x1, x2, . . . , xn, we wish to make change for a value v; that is, we wish to find a set of coins whose total value is v. This might not be possible: for instance, if the denominations are 5 and 10, then we can make change for 15 but not for 12. Give an O(nv) dynamic programming algorithm for the following problem. Input: x1, . . . , xn; v. Question: Is it possible to make change for v using coins of denomination

When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?

Create a string list. 2. use console. readline() to collect values of firstname, lastname, street, city, state, zip, save them to list. 3. write a simple linq statement, call method uppercasewords() to change first letter to uppercase. 4. create a foreach statment to display the information. public static string uppercasewords(string value) { char[] array = value. tochararray(); if (array. length > = 1) { if (char. islower(array[0])) { array[0] = char. toupper(array[0]); } } for (int i = 1; i < array. length; i++) { if (array[i - 1] == ' ') { if (char. islower(array[i])) { array[i] = char. toupper(array[i]); } } } return new string(array);

Which best describes the condition under which the unicode output is the same as plain text ?