Computers and Technology, 23.04.2020 21:22, bear342
INDIVIDUAL ASSIGNMENT: See the course syllabus for a definition of what constitutes an individual assignment. Task 1 (of 2) The tasks for the In-Class Activity on Day 1 of Week 12 were focused on plotting and the Method of Selected Points (MSP). The purpose of this task is to develop a Python script which will determine an estimated equation of best fit using the MSP. For this task, you can assume the data has already been plotted and an estimated line of best fit has been drawn. Your script should allow the user to input the two data points they selected from their estimated equation of best fit. The user should also input the type of axes the data was plotted on (linear, log-log, or semi-log). A set of conditional statements should be used to calculate m and b based on the type of axes on which the data was plotted. The script should then output the estimated equation of best fit with the m and b values included in the equation in the form below. You do not need to provide any plots. Linear: y = m_value*x + b_value Power: y = b_value*x^m_value Exponential: y = b_value*e^(m_value*x) Test Cases: You should use the In-Class Act
Answers: 3
Computers and Technology, 23.06.2019 03:00, minelly1717
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Computers and Technology, 23.06.2019 17:30, Annlee23
When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?
Answers: 2
INDIVIDUAL ASSIGNMENT: See the course syllabus for a definition of what constitutes an individual as...
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