Premise: Tracy has a file that contains a list of actors and the movies in which they acted. She wants to know the top 3 ranked actors from her list whom have acted/appeared in the most movies. ACTOR_NAME MOVIE_NAME Leonardo DiCaprio The Revenant Christian Bale Vice Morgan Freeman Shawshank Redemption Leonardo DiCaprio The Great Gatsby Christian Bale American Psycho Morgan Freeman The Dark Knight Christian Bale The Dark Knight Samuel L. Jackson Pulp Fiction Question: Write code in Java/Scala/Python to display the top 3 ranked actors appearing in the most movies based on the count of movies in which they have acted. If there are less than 3 actors in her list, display all of them. Consider all scenarios - such as, if two actors have acted in the same number of movies, they will have the same rank.

see explaination

Explanation:

Python version : 2.7

Python program to read an input file with specified number of records to read

and output the top 3 ranked actors

The format of input file:

<number of records to read>

<actor_name>,<movie_name>

<actor_name>,<movie_name>

....

'''

#define the file name

filename = 'actors_movies.txt'

# create an empty dictionary to contain the actor name as key and number of movies they have acted as value

actors_movie_count = {}

# open the flie

fp = open(filename)

line = fp.readline() # read the first line

count = int(line)

i = 0

# loop to read count number of lines from file

while i < count:

line = fp.readline() # read a line

data = line.split(",") # split the input data into list of strings using comma as the delimiter

# check if actor name is present in the dictionary, then add 1 to its value

# strip is used to remove any leading or trailing space

if data[0].strip() in actors_movie_count:

actors_movie_count[data[0].strip()] += 1

else: # else insert a new record with actor name as its key and 1 as value

actors_movie_count[data[0].strip()] = 1

i += 1

# close the file

fp.close()

# get the list of names of actors and list of number of movies they have acted

actors = actors_movie_count.keys()

num_movies = actors_movie_count.values()

# loop to sort the actors list and num_movies list in descending order of count of movies

for i in range(len(num_movies)-1):

max = i

for j in range(i+1,len(num_movies)):

if num_movies[j] > num_movies[max]:

max = j

if max != i:

actors[max], actors[i] = actors[i], actors[max]

num_movies[max], num_movies[i] = num_movies[i], num_movies[max]

# rank the actors to add top 3 ranked actors to rank_actors list

rank = 1

rank_actors = []

# add the first actor to list

rank_actors.append(actors[0])

# loop from second to end of actors list

for i in range(1,len(actors)):

# if this actor has same number of movies as the actor before him, then assign same rank

if num_movies[i] == num_movies[i-1]:

# if rank <= 3, add the actor in rank_actors list

if rank <= 3:

rank_actors.append(actors[i])

else: # rank > 3, exit the loop

break

else: # assign 1 more rank that the previous

rank += 1

# if rank <= 3, add the actor in rank_actors list

if rank <= 3:

rank_actors.append(actors[i])

else: # rank > 3, exit the loop

break

# loop to display the top 3 ranked actors

for actor in rank_actors:

print(actor)

#end of program

see attachment for the program screenshot and output

i would say 3 because windows is the best but vista doesnt do updates anymore