Light whose wavelength is 565 is incident on a 0.00600 wide slit. At what angle is the first diffraction minimum located??
Physics

The first diffraction minimum located at an angle of 5.40°.

Explanation:

Here the wavelength, λ = 565 nm = 565 × 10⁻⁹ m

Width of the slit, d = 0.00600 mm = 6 × 10⁻⁶ m

We need to find the angle as,

sin θ = mλ / d

We have to find the angle as,

θ  = sin⁻¹ ( mλ / d )

Here m = 1,

θ = sin⁻¹ ( )

  = sin⁻¹(0.0942)

  = 5.40°

So the first diffraction minimum located at an angle of 5.40°.

answer; code of ethicsi believe is the correct answer;

a.s= 230t– 110; 1500 lbc.t= 230s– 110; 1500 lbb.s= 230t+ 110; 1720 lbd.s= 199t– 110; 1280 lb