Design a 16K x 8 memory using the following ICs:

a. 1024 x1

b. 2K x4

c. 1Kx 8

Each IC has on-chip decoding, tristate outputs, and an enable pin.

d. Arrange the 16 chips needed in the design of problem (b) as a 4x 4 array and design the decoding circuitry.

Required memory size is 16k x 8

16k = 24 x 210 = 214

Hence, No. of address lines = 14

No. of data lines = 8

a) Size of IC 1024 x 1

Total number of ICs required = 16k x 8 / 1024 x 1 = 16 x 8 = 128

b) Size of IC 2k x 4

Total number of ICs required = 16k x 8 / 2k x 4 = 8 x 2 = 16

c) Size of IC 1k x 8

Total number of ICs required = 16k x 8 / 1k x 8 = 16 x 1 = 16

Explanation:

For a, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1024 memory locations present in a IC.

For b, 11 address lines from A0 to A10 are used to select any one of the memory location out of 2k=2048 memory locations present in a IC.

For c, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1k=1024 memory locations present in a IC.

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