Write a function "nonRepeatings" that takes a string "s3" and returns the non-repeating characters in this string. Sample Input s3 = "aaazzzdcccrttt" Sample Output The non-repeating characters are; d ryou are suppose to use for loops to go throw and return a dictionary of non repeating letters.

def nonRepeatings(s3):

   non = []

   letter_dictionary = {}

   for l in s3:

       if l in letter_dictionary:

           letter_dictionary[l] += 1

       else:

           letter_dictionary[l] = 1

   for c in letter_dictionary:

       if letter_dictionary[c] == 1:

           non.append(c)

   return non

Explanation:

- Declare an empty list and a dictionary

- Initialize a for loop that iterates through the given string s3

Inside the loop:

- If a character in the string is in the dictionary, increment its count by 1. If not, add it to the dictionary

When the first loop is done, initialize another for loop that iterates through the dictionary.

- Inside the loop, check if any character has a value of 1, put it to the non.

- Finally, return the non

solution:

this situation is called an ip conflict.

data from a server is sent in small bits called packets. in an ip conflict, some packets will end up in one computer while some other packets will end up in another computer.

so…overall none of the computers get the data as the original message or picture being sent by the server cannot be retrieved with only half the packets. so it will show up as an error.

thus the final answer is d.

answer ingress;