Computers and Technology, 31.03.2020 01:28, dudeper40
Marty is investigating the computer of a cyberstalking suspect. He wanted to check the suspect's browsing history in Microsoft Internet Explorer but it had already been erased. Where else can he look on the computer for browsing history information
Answers: 3
Computers and Technology, 22.06.2019 11:30, lindalu
Hassan is writing his master’s thesis, which is a thirty-page document. he received some feedback from his professor in the form of comments, but does not see where the comments are. what is the fastest way for hassan to find the feedback?
Answers: 3
Computers and Technology, 22.06.2019 20:00, Jana1517
What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i. e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }
Answers: 3
Computers and Technology, 23.06.2019 01:20, shiann2002
Me with this program in c++ ! computers represent color by combining sub-colors red, green, and blue (rgb). each sub-color's value can range from 0 to 255. thus (255, 0, 0) is bright red. (130, 0, 130) is a medium purple. (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (in other word, equal amounts of red, green, blue yield gray).given values for red, green, and blue, remove the gray part. ex: if the input is 130 50 130, the output is: 80 0 80. thus, find the smallest value, and then subtract it from all three values, thus removing the gray.
Answers: 3
Marty is investigating the computer of a cyberstalking suspect. He wanted to check the suspect's bro...
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