The IBM nine-track tapes that became the industry standard for storage for three decades had several sizes , the most common being 2400 feet. The high density version stored data at 1600 bits/inch/track. If the whole tape (not including the parity track) could be used for data storage , how much raw data could one of these tapes hold?

5 MB.

Explanation:

1 foot = 12 inches

2400/9=266.66 feet per track

1 track excluding, remaining 8 track =2400 - 266.66 = 2133.33 feet

so, space available to store data = 2133.33 feet

now, 2133.33 feet = 25600 inches

total data that can be stored = 25600 * 1600 = 40960000 bits

= 46080000/8 = 5120000 Bytes

= 5120000/1000000 = 5.12 MB = 5 MB (approx.)

given the options, i would say your best bet is c. the modem supports up to 56 kbps, which is too low for video streaming. dial up modems use actual phone lines, which only can go up to 56 kbps as that's more than sufficient for traditional phone calls. this is also the reason why when a dial-up modem connects, you hear all those sounds. it's literally using the phone line to establish a connection.