Computers and Technology, 23.03.2020 18:22, jolleyrancher78

Creating an accurate inventory is a challenge, given the speed at which data files are created, deleted, moved, and changed. It is therefore recommend that an organization prioritize the inventory of assets, starting with the least sensitive to most sensitive. True / False.

Answers: 1

Show answers

Other questions on the subject: Computers and Technology

Computers and Technology, 22.06.2019 06:30, miguel3maroghi

This technology is used to produce high-quality documents that look good on the computer screen and in print. wiki presentation paint desktop publishing

Answers: 3

continue

Computers and Technology, 22.06.2019 08:00, Leggett8152

What best describes a career pathway in a lodging career? a worker starts out as an amusement attendant, then becomes a recreation worker, and then becomes a gaming worker within five years. a worker starts out as a bell hop, then becomes a night clerk, and then becomes a hotel manager within five years. a worker starting out as a tour guide, then becomes a travel clerk, and then becomes a travel agent within five years. a worker starts out as a server, then becomes a food preparer, and then becomes a head chef within five years.

Answers: 1

continue

Computers and Technology, 22.06.2019 18:30, Angelanova69134

Technician a says that a shop towel should never be used to clean around the flange area before replacing an automatic transmission filter. technician b says that a dimpled transmission fluid pan can be repaired. who is right

Answers: 3

continue

Computers and Technology, 22.06.2019 20:00, Jana1517

What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i. e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }

Answers: 3

continue

Do you know the correct answer?

Creating an accurate inventory is a challenge, given the speed at which data files are created, dele...