Computers and Technology
Computers and Technology, 16.03.2020 16:37, sunny3799

Complete the do-while loop to output every number form 0 to countLimit using printVal. Assume the user will only input a positive number. For example, if countLimit is 5 the expected output will be 0 1 2 3 4 5

import java. util. Scanner;

public class CountToLimit {

public static void main (String [] args) {

Scanner scnr = new Scanner(System. in);

int countLimit = 0;

int printVal = 0;

// Get user input

countLimit = scnr. nextInt();

printVal = 0;

do {

System. out. print(printVal + " ");

printVal = printVal + 1;

} while ( /* Your solution goes here */ );

System. out. println("");

return;

}

}

Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less than 100. End each prompt with newline Ex: For the user input 123, 395, 25, the expected output is:

Enter a number (<100):
Enter a number (<100):
Enter a number (<100):
Your number < 100 is: 25
import java. util. Scanner;

public class NumberPrompt {

public static void main (String [] args) {

Scanner scnr = new Scanner(System. in);

int userInput = 0;

/* Your solution goes here */

System. out. println("Your number < 100 is: " + userInput);

return;

}

}

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