Computers and Technology, 10.03.2020 00:31, lilquongohard
An approximation to the integral of a function f(x) over an interval [a, b] can be found by first approximating f(x) by the straight line that goes through the end points (a, f(a)) and (b, f(b)), and then finding the area under the straight line, which is the area of the trapezoid. The resulting formula becomes:
lim(a→b) ∫ f(x)d(x) = (b-a)/2[f(a) + f(b)]
Write a function trapezint1( f, a,b) that returns this approximation to the integral. The argument f is a Python implementation f(x) of the mathematical function f(c). For instance, the result of trapezint1( math. sin,0,0.5* math. pi ) should be 0.7854 (with some numerical error). The result of trapezint1( abs, -1,1 ) should be 2.0.
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Computers and Technology, 22.06.2019 22:30, kierafisher05
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An approximation to the integral of a function f(x) over an interval [a, b] can be found by first ap...
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