In this assignment you'll write a program that encrypts the alphabetic letters in a file using the Vigenère cipher. Your program will take two command line parameters containing the names of the file storing the encryption key and the file to be encrypted. The program must generate output to the console (terminal) screen as specified below. Command Line Parameters 1. Your program must compile and run from the command line. 2. Input the required file names as command line parameters. Your program may NOT prompt the user to enter the file names. The first parameter must be the name of the encryption key file, as described below. The second parameter must be the name of the file to be encrypted, as also described below. The sample run command near the end of this document contains an example of how the parameters will be entered. 3. Your program should open the two files, echo the processed input to the screen, make the necessary calculations, and then output the ciphertext to the console (terminal) screen in the format described below. Note: If the plaintext file to be encrypted doesn't have the proper number (512) of alphabetic characters, pad the last block as necessary with the letter 'X'. Make sure

C code is given below

Explanation:

// Vigenere cipher

#include <ctype.h>

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

/**

* Reading key file.

*/

char *readFile(char *fileName) {

   FILE *file = fopen(fileName, "r");

   char *code;

   size_t n = 0;

   int c;

   if (file == NULL) return NULL; //could not open file

   code = (char *)malloc(513);

   while ((c = fgetc(file)) != EOF) {

      if( !isalpha(c) )

          continue;

      if( isupper(c) )

          c = tolower(c);

      code[n++] = (char)c;

   }

   code[n] = '\0';

  fclose(file);

   return code;

}

int main(int argc, char ** argv){  

   // Check if correct # of arguments given

   if (argc != 3) {

       printf("Wrong number of arguments. Please try again.\n");

       return 1;

   }

  // try to read the key file

  char *key = readFile(argv[1]);

  if( !key ) {

      printf( "Invalid file %s\n", argv[1] );

      return 1;

  }

  char *data = readFile(argv[2]);

  if( !data ) {

      printf("Invalid file %s\n", argv[2] );

      return 1;

  }

   // Store key as string and get length

   int kLen = strlen(key);

  int dataLen = strlen( data );

  printf("%s\n", key );

  printf("%s\n", data );

  int paddingLength = dataLen % kLen;

  if( kLen > dataLen ) {

      paddingLength = kLen - dataLen;

  }

  for( int i = 0; i < paddingLength && dataLen + paddingLength <= 512; i++ ) {

      data[ dataLen + i ] = 'x';

  }

  dataLen += paddingLength;

   // Loop through text

   for (int i = 0, j = 0, n = dataLen; i < n; i++) {          

       // Get key for this letter

       int letterKey = tolower(key[j % kLen]) - 'a';

       // Keep case of letter

       if (isupper(data[i])) {

           // Get modulo number and add to appropriate case

           printf("%c", 'A' + (data[i] - 'A' + letterKey) % 26);

           // Only increment j when used

           j++;

       }

       else if (islower(data[i])) {

           printf("%c", 'a' + (data[i] - 'a' + letterKey) % 26);

           j++;

       }

       else {

           // return unchanged

           printf("%c", data[i]);

       }

      if( (i+1) % 80 == 0 ) {

          printf("\n");

      }

   }

   printf("\n");

   return 0;

}

code is written in c++ below

Explanation:

// C++ code to implement Vigenere Cipher

#include<bits/stdc++.h>

using namespace std;

// This function generates the key in

// a cyclic manner until it's length isi'nt

// equal to the length of original text

string generateKey(string str, string key)

{

int x = str.size();

for (int i = 0; ; i++)

{

if (x == i)

i = 0;

if (key.size() == str.size())

break;

key.push_back(key[i]);

}

return key;

}

// This function returns the encrypted text

// generated with the help of the key

string cipherText(string str, string key)

{

string cipher_text;

for (int i = 0; i < str.size(); i++)

{

// converting in range 0-25

int x = (str[i] + key[i]) %26;

// convert into alphabets(ASCII)

x += 'A';

cipher_text.push_back(x);

}

return cipher_text;

}

// This function decrypts the encrypted text

// and returns the original text

string originalText(string cipher_text, string key)

{

string orig_text;

for (int i = 0 ; i < cipher_text.size(); i++)

{

// converting in range 0-25

int x = (cipher_text[i] - key[i] + 26) %26;

// convert into alphabets(ASCII)

x += 'A';

orig_text.push_back(x);

}

return orig_text;

}

// Driver program to test the above function

int main()

{

string str = "GEEKSFORGEEKS";

string keyword = "AYUSH";

string key = generateKey(str, keyword);

string cipher_text = cipherText(str, key);

cout << "Ciphertext : "

<< cipher_text << "\n";

cout << "Original/Decrypted Text : "

<< originalText(cipher_text, key);

return 0;

}

yes we can change both the color of the value of a cell as well as background color of a cell at the same time .

as we know that excel sheet consists of columns and rows.

and intersection of column and row is called cell.

we can change color of the cell and background of the cell at the same time.

hence the statement that

can a person change color of the cell and background of the cell at the same time is true.