Write a while loop that prints userNum divided by 4 (integer division) until reaching 2. Follow each number by a space. Example output for userNum = 160:

40 10 2

Note: These activities may test code with different test values. This activity will perform four tests, with userNum = 160, then with userNum = 8, then with userNum = 0, then with userNum = -1. See "How to Use zyBooks".

Also note: If the submitted code has an infinite loop, the system will stop running the code after a few seconds, and report "Programend never reached." The system doesn't print the test case that caused the reported message.

#include
using namespace std;

int main() {
int userNum;

cin >> userNum;

/* Your solution goes here */

cout << endl;

return 0;
}

Answer / Explanation:

#include <iostream>  

using namespace std;

int main()  

{    

 int userNum = 0;  

  userNum = 20;    

  cout << userNum << " ";

  while (userNum > 1)    

  {

     userNum = userNum/2;

     cout << userNum << " ";    

  }    

  cout << endl;  

  return 0;  

}

However, we should note that the above codes divides properly but when it gets to 0, it will always give output as 0 instead of terminating the program.

Hence to make it terminate, we include:

while (userNum > 1)    

{

  cout << userNum << " ";    

  userNum = userNum/2;

}    

The above code alternatively should be replaced with int userNum = 0;  .

Also, for the sake of industry best standard and the general principle, we can say:

The general principle is:

while ( <conditional> )

{

  // Use the data

  // Change the data as the last operation in the loop.

}

A for loop provides natural placeholders for these.

for ( <initialize data>; <conditional>; <update data for next iteration> )

{

  // Use the data

}  

If you were to switch to using a for loop, which I recommend, your code would be:

for ( userNum = 20; userNum > 0; userNum /= 2 )

{

  cout << userNum << " ";

i think its controle not shift