A variable c of type char has been declared. Write the necessary code to read in the next character from standard input and store it in c, regardless of whether is a whitespace character.

import java.util.Scanner;

public class num3 {

   public static void main(String[] args) {

       char c;

       Scanner in = new Scanner(System.in);

       c = in.nextLine().charAt(0);

   }

}

Explanation:

Using Java Programming language. Variable c of type char is declaredScanner class is imported to receive user inputthe string method nextLine is used to read an entire line including whitespacecharAt(0) returns the first character which is assigned to c

The health and well being of people employed in a work environment.

(1)correct answer is d.the others are just bad syntax.by using the keyword "new" and int[] together, you create a new integer array object in memory. whenever you want to create an object without using array literals, you must use new. (by array literals, i mean a line of declaration code like int[] x = {4,6}; where you literally specify an array without using new. an array literal can only be used in the same line as declaring the array.)(2)correct answer is c. it is the only choice that returns an array and properly takes in an array reference as an argument.choices a and b do not return an array; they respectively return void (nothing at all) and a primitive double, which is not a double array.choice d has invalid syntax. looking at it, it won't properly accept any array reference you pass into the method.(3)correct answer is a.x is already defined.choice b only returns an index of the array.also, in any other method, you wouldn't write the type next to the thing being returned. choices c and d are invalid.(4)correct answer is c.choice a only accepts one.choice b requires at least two numbers.choice d only takes in an integer array reference, not integers.(5) correct choice is d.by specifying that the first argument can take in any number of ints, java will assume everything you input into the method will be an integer.theoretically it will never reach that string argument, no matter how many commas you put. this is illegal; the java compiler will complain. i don't think it'll even recognize it as a method header.