Computers and Technology

Consider the following program, which consists of two object modules: 1 /* foo6.c */ 2 void p2(void); 3 4 int main() 5 { 6 p2(); 7 return 0; 8 } 1 /* bar6.c */ 2 #include 3 4 char main; 5 6 void p2() 7 { 8 printf("0x%x\n", main); 9 } When this program is compiled and executed on an x86-64 Linux system, it prints the string 0x48\n and terminates normally, even though function p2 never initializes variable main. Can you explain this?

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Consider the following program, which consists of two object modules: 1 /* foo6.c */ 2 void p2(void)...

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