Consider the following set of processes, with the length of the CPU burst
given in milliseconds:
Process Burst Time Priority
P1 2 2
P2 1 1
P3 8 4
P4 4 2
P5 5 3
The processes are assumed to have arrived in the order P1, P2, P3, P4, P5,
all at time 0.
a. Draw four Gantt charts that illustrate the execution of these
processes using the following scheduling algorithms: FCFS, SJF,
nonpreemptive priority (a larger priority number implies a higher
priority), and RR (quantum = 2).
b. What is the turnaround time of each process for each of the
scheduling algorithms in part a?
c. What is the waiting time of each process for each of these scheduling
algorithms?
d. Which of the algorithms results in the minimum average waiting
time (over all processes)?

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given the lack of choices, i'm gonna wing it and say that pushing your car off a cliff might not be the best idea. your car might sustain damage from the fall and will probably result in the car being too damaged to jump start.

if that's not good enough, avoid filling the car with bees. bees might get agitated when trapped or during the moving process, and might result in death or painful stings that will make jump starting your car very difficult. but in the event that you do choose to fill your car with bees, remember to wear protective gear!