#include
#include

int main( )
{
int pid;
int value = 5;

pid = fork( );
if (pid == 0)
{
execlp("/bin/ls", "ls", NULL);
value += 10;
printf(value);
} else
{
wait(NULL);
}

return 0;
}
What output is printed on the screen when the above program is executed?

a. No output is printed on the screen
b.15
c.5
d.10

a.No output is printed on the screen

Explanation:

As is the function an error will be printed because fork() is not declared in the scope, to define an output we need to see the full content of the code; because 'value' is an integer the 'printf' function is not well defined and the library for execlp is not defined; in general, this code will throw multiple errors in execution.

its true for the one time