In a nondatabase, file-oriented environment, data is often partitioned into several disjointed systems with each system having its own collection of files.

a. true
b. false

Consider a direct-mapped cache with 216 words in main memory. the cache has 16 blocks of 8 words each. it is a word-addressable computer (rather than a byte-addressable computer which we normally discuss). (a) how many blocks of main memory are there? (b) what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, cache block, and block offset fields (if they apply)? (c) to which cache block will the memory reference db6316 map?

How would you categorize the software that runs on mobile devices? break down these apps into at least three basic categories and give an example of each.

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words. size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words. size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }