You are given a list of numbers for which you need to construct a **min**-heap. (a **min**-heap is a complete binary tree in which every key is less than or equal to the keys in its children.) how would you use an algorithm for constructing a **max**-heap (a heap as defined in section 6.4) to construct a **min**-heap? you need to describe your algorithm in **pseudo code**.

Events and conditions that happen within an organization that are somewhat easier to deal with when responding to change are called

In my email i got a message it says a quick message and in message details on who its from its says nicole and under nicole is 50e0bf08e5b671@ualwgypg91wa5wl. uzo9kbud3qjwddygd5.vng -

Fill in the following program so that it will correctly calculate the price of the orange juice the user is buying based on the buy one get one sale.#include //main functionint main() { int cartons; float price, total; //prompt user for input information printf("what is the cost of one container of oj in dollars? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & price); printf("how many containers are you buying? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & cartons); if ( [ select ] ["cartons / 2", "cartons % 1", "cartons % 2", "cartons % price", "cartons / price", "cartons / total"] [ select ] ["=", "==", "! =", "< =", "> =", "< "] 0) total = [ select ] ["price * cartons", "cartons * price / 2 + price", "(cartons / 2) * price", "cartons / (2.0 * price)", "(cartons / 2.0) * price + price", "((cartons / 2) * price) + price"] ; else total = ((cartons / 2) * price) + price; printf("the total cost is $%.2f.\n", total); return 0; }