The variable 'a' starts with the value 1 the variable 'b' starts with the value 10 the variable 'c' starts with the value 100 the variable 'x' starts with the value 0 store the value of 'c' times 3 in 'x' add the value of 'b' times 6 to the value already in 'x' add the value of 'a' time 5 to the value already in 'x' display the value of 'x' on the screen.

a. 355
b. 365
c. 325
d. 370

The answer is B = 365

Explanation:

The following variable were initialized:

a = 1

b = 10

c = 100

x = 0

Then we store the value of 'c' times 3 in 'x'

x = 3 * c = 3 * 100 = 300

x = 300

Then we add the value of 'b' times 6 to the value already in 'x'

x = x + 'b' times 6

x = x + (b * 6) = 300 + (10 * 6) = 300 + 60 = 360

x = 360

Then we add the value of 'a' times 5 to the value already in 'x'

x = x + 'a' times 5

x = x + (a * 5) = 360 + (1 * 5) = 360 + 5 = 365

x = 365.

Therefore, the value of 'x' displayed is 365.

sory but complete the question