Consider the following code: public static void mystery(int a) { system. out. println("a"); } public static void mystery(double a) { system. out. println("b"); } public static void mystery(int a, double b) { system. out. println("c"); } public static void mystery(double a, int b) { system. out. println("d"); } what is output by the following? mystery(7);

The output is "A"

Explanation:

public class Solution {

   public static void main(String args[]) {

     mystery(7);

   }    

   public static void mystery(int a) { System.out.println("A"); }    

   public static void mystery(double a) { System.out.println("B"); }    

   public static void mystery(int a, double b) { System.out.println("C"); }    

   public static void mystery(double a, int b) { System.out.println("D"); }

}

In the code above; mystery is defined in four different ways called method overloading. Method overloading is when same method is defined with different parameters.

In the first case; mystery will be called if the argument is int.

In the second case; mystery will be called if the argument is double.

In the third case; mystery will be called if the arguments are int and double.

In the fourth case; mystery will be called if the arguments are double and int.

When mystery(7) is called; the mystery method requiring only int will be called and the output is "A".

answer; i believe the answer is (on both rear

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explanation:

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