Given an input array of strings (characters) s, pick out the second column of data and convert it into a column vector of data. missing data will be indicated by the number . if you encounter missing data, you should set it to the average of the immediately neighboring values. (this is a bit simpler than using `interp1`.)
if the input array is s = [ 'a' '0096' ; 'b' '0114' ; 'c' '' ; 'd' '0105' ; 'e' '0112' ]; then the output variable `t` is the following column vector. t = [96 114 109.5 105 112]';
compose a function read_and_interp which accepts an array in the above format and returns the data converted as specified. you may find the conversion function `str2num` to be useful.
(using matlab syntax only)

Consider the following code.

Explanation:

save the following code in read_and_interp.m

function X = read_and_interp(s)

[m, n] = size(s);

X = zeros(m, 1);

for i = 1:m

if(str2num(s(i, 2:5)) == 9999)

% compute value based on previous and next entries in s array

% s(i, 2:5) retrieves columns 2-5 in ith row

X(i,1) = (str2num(s(i-1 ,2:5)) + str2num(s(i+1,2:5)))/2;

else

X(i,1) = str2num(s(i,2:5));

end

end

end

Now you can use teh function as shown below

s = [ 'A' '0096' ; 'B' '0114' ; 'C' '9999' ; 'D' '0105' ; 'E' '0112' ];

read_and_interp(s)

output

ans =

96.000

114.000

109.500

105.000

112.000

por su calidadad

explanation:

you go to add your answer type bewteen 5000 and 20 characters and can only have 2 people answer on 1 question.your challanges are based on your questions.