Calculate the total number of bits required for the cache listed above, assuming a 32-bit address. given that total size, fi nd the total size of the closest direct-mapped cache with 16-word blocks of equal size or greater. explain why the second cache, despite its larger data size, might provide slower performance than the fi rst cache.

Number of bits in a cache = 2588672 bits

Cache with 16- word block of equal size or greater =4308992

Explanation:

To calculate the number of bits required for the cache containing 32- bit address.

formula to calculate the bits is :

Number of bits in a cache

total bits = = 2588672 bits

Cache with 16- word block of equal size or greater

total bits = =4308992

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explanation:

solution:

the right option is a

to adding   a new row to a table we   have to do process last table cell and pressing tab.

this is the process to add new row in the cell:

* to add a row below the cell, click insert below in the rows and columns group.

thus this is the required right answer.