Your program will read a word (or a whole line) from the user. it will then count the number of vowels in the word (or line) and print put this value. you should ignore the semi-vowel y since determining its role requires dividing words into syllables which is hard to do in english. the program should end when the word end is entered. example input and output: enter a word: vowel the word vowel contains 2 vowels. enter a word: determining the word determining contains 4 vowels. enter a word: will the word will contains 1 vowel. enter a word: end

Following are the program in the Python Programming Language.

def vowel(): #define function

 print("Enter END to Break") #print message

 while(True): #set while loop

   word=input("Enter words: ") #get input from the user

   count=0 #set count to 0

   if(word=="END"): #set if condition

     break #terminate the loop

   else:

     for i in range(len(word)): #set the for loop

       c=word[i] #initialize in c

       if(c=='a'or c=='e' or c=='i'or c=='o'or c=='u'or c=='A'or c=='E'or c=='I'or c=='O'or c=='U'):

         count+=1 #increament in count by 1

     print("The word " , word , " contains " , count, end=" ")#print message

     if(count==1):#check condition

       print("vowel.")

     else:

       print("vowels")

#call the function

vowel()

Output:

Enter END to Break

Enter words: Vowel

The word  Vowel  contains  2 vowels

Enter words: END

Explanation:

Here, we define a function "vowel()" inside it.

Finally, we call the following function "vowel()".

solution:

the right option is a

to adding   a new row to a table we   have to do process last table cell and pressing tab.

this is the process to add new row in the cell:

* to add a row below the cell, click insert below in the rows and columns group.

thus this is the required right answer.