Computers and Technology, 05.12.2019 17:31, 970032036
Write a function safeopen() that takes one parameter, filename — a string giving the pathname of the file to be opened for reading. when safeopen() is used to open a file, a reference to the opened file object should be returned if no exception is raised, just like for the open() function. if an exception is raised while trying to open the file, safeopen() should return the value none.
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Computers and Technology, 02.08.2019 19:10, psitthibun
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Computers and Technology, 21.09.2019 11:50, clmorcutt420
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Computers and Technology, 08.11.2019 00:31, arugg2k24
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