Aslide can have which of the following?
a) more than one title text box
b) more t...
Computers and Technology, 03.12.2019 21:31, LucidDreamer16
Aslide can have which of the following?
a) more than one title text box
b) more than one text box
c) text box and drawing objects
d) all of these
Answers: 2
Computers and Technology, 22.06.2019 20:00, Jana1517
What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i. e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }
Answers: 3
Computers and Technology, 22.06.2019 21:00, jarrettashlyn
Write a method so that the main() code below can be replaced by the simpler code that calls method original main(): public class calcmiles { public static void main(string [] args) { double milesperhour; double minutestraveled; double hourstraveled; double milestraveled; milesprhour = scnr. nextdouble(); minutestraveled = scnr. nextdouble(); hourstraveled = minutestraveled / 60.0; milestraveled = hourstraveled * milesperhour; system. out. println("miles: " + milestraveled); } }
Answers: 2
Computers and Technology, 23.06.2019 00:40, QueenKy6050
Consider the following statements: struct nametype{string first; string last; }; struct coursetype{string name; int callnum; int credits; char grade; }; struct studenttype{nametype name; double gpa; coursetype course; }; studenttype student; studenttype classlist[100]; coursetype course; nametype name; mark the following statements as valid or invalid. if a statement is invalid, explain why. a.) student. course. callnum = "csc230"; b.) cin > > student. name; c.) classlist[0] = name; d.) classlist[1].gpa = 3.45; e.) name = classlist[15].name; f.) student. name = name; g.) cout < < classlist[10] < < endl; h.) for (int j = 0; j < 100; j++)classlist[j].name = name; i.) classlist. course. credits = 3; j.) course = studenttype. course;
Answers: 1
Mathematics, 06.05.2020 01:14
Computers and Technology, 06.05.2020 01:14