Define a function pyramidvolume with double parameters baselength, basewidth, and pyramidheight, that returns as a double the volume of a pyramid with a rectangular base. relevant geometry equations: volume = base area x height x 1/3 base area = base length x base width. (watch out for integer division).

The Program to this question can be given as:

Program:

#include <iostream> //header file.

using namespace std;

double PyramidVolume(double baseLength, double baseWidth, double pyramidHeight)  //define a method PyramidVolume

{

   double baseArea,Volume; //declare variable.

   baseArea= baseLength * baseWidth;  //calculate baseArea

   Volume = ((baseArea * pyramidHeight) * 1/3);  //calculate Volume

   return Volume; //return Volume

}

int main() //define main method.

{

double x,baseLength,baseWidth,pyramidHeight; //define variable.

cout<<"Enter baseLength :"; //message.

cin>>baseLength; //input value.

cout<<"Enter baseWidth :";//message.

cin>>baseWidth;  //input value.

cout<<"Enter pyramidHeight :";//message.

cin>>pyramidHeight;  //input value.

x=PyramidVolume(baseLength,baseWidth,pyramidHeight); //calling

cout << "Volume of given value is :"<<x; //print value.

return 0;

}

Output:

Enter baseLength :1.0

Enter baseWidth :1.0

Enter pyramidHeight :1.0

Volume of given value is :0.333333

Explanation:

The description of the above program can be given as: