Refer to the exhibit. which two network addresses can be assigned to the network containing 10 hosts? your answers should waste the fewest addresses, not reuse addresses that are already assigned, and stay within the 10.18.10.0/24 range of addresses. (choose two.)
a. 10.18.10.200/28
b. 10.18.10.208/28
c. 10.18.10.224/28
d. 10.18.10.200/27
e. 10.18.10.224/27

As result as follows these two network addresses can be assigned to the network containing 10 hosts:

B. 10.18.10.208/28

C. 10.18.10.224/28

Explanation:

Since 10.18.10.0/24 depends on subnet also.  10.18.10.0 To 10.18.10.63 is taken to leftmost network address. Since it is 4 host bits, it required to accommodate 10 hosts.  And it marks to be in end with /28.

And more over 10.18.10.200/28 should be invalid network number. Moreover other one ends with /27 it is invalid to this specific ranges of tcpip address.

Other 10.18.10.200/27 or 10.18.10.224/27 is falls in invalid range, because it ends with /27

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