Computers and Technology, 12.11.2019 05:31, tonio638

Which value can be entered to cause the following code segment to display the message: "that number is acceptable." int number; cin > > number; if (number > 10 & & number < 100) cout < < "that number is acceptable.\n"; else cout < < "that number is not acceptable.\n";

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Computers and Technology, 04.07.2019 20:10, ella3714

Construct a complete c++ program from the following conditions; (note your code 1. should include appropriatecomments); 1- user must enter "start" to start the program 2- user are able to enter any characters and floating point number. 3- if user entered character between 'a' to 'g' or number between 1 to 25.789, display "level 1". 4- if user entered character between 'h' to 'm' and number between 26 to 30.789, display "level 2" 5-if user entered other characters or other numbers, display "level 3"

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Computers and Technology, 29.08.2019 16:30, kendrawalraven

Which value can be entered to cause the following code segment to display the message "that number is acceptable." int number cin > > number; if (number > 10 & & number < 100) cout < < "that number is acceptable."; else cout < < "that number is not acceptable."

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Computers and Technology, 18.09.2019 22:10, irvinanderson

Write a program that asks the user to enter a number of seconds. • there are 60 seconds in a minute. if the number of seconds entered by the user is greater than or equal to 60, the program should display the number of minutes in that many seconds. programming challenges 185 the time calculator problem videonote 186 chapter 3 decision structures • there are 3,600 seconds in an hour. if the number of seconds entered by the user is greater than or equal to 3,600, the program should display the number of hours in that many seconds. • there are 86,400 seconds in a day. if the number of seconds entered by the user is greater than or equal to 86,400, the program should display the number of days in that many seconds.

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Computers and Technology, 30.10.2019 01:31, cxttiemsp021

Hello, i have to build a program using assembly with mars system. the program is supposed to return a hailstone sequence a)- get user input (integer) - n b) check if even or odd - if the input is even, the next number should n/2 - if the user's input (n*3)+1 c) reproduce the operation on the next number until the number is equal to 1 d) display the sequence e) count and display the number of iterartion i have the user input done, and then, i tried to do a bitwise operation using and to see if the number is even or not but the program doesn't work after the user's input, as i have an output equal to zero can you me ? here is my code so far .data prompt: .asciiz "enter an integer: " message1: .asciiz "you entered an even number" message2: .asciiz "you entered an odd number" message3: .asciiz "and the next numbers should be: " gototheline: .asciiz "\n" message4: .asciiz "you just entered the number: " .text main: #print the prompt li $v0,4 la $a0,prompt syscall #get the user's input li $v0,5 syscall #store the input'svalue move $t3, $v0 #display the user's input message li $v0,4 la $a0,message4 syscall #go to the line li $v0,4 la $a0,gototheline syscall #print value entered by user li $v0,1 move $a0, $t3 syscall #go to the line li $v0,4 la $a0,gototheline syscall #bitwise operation on the input and $a0,$0,1 #call odd function if number is odd beq $a0,1,ifodd #print next number message li $v0, 4 la,$a0,message3 syscall #go to the line li $v0,4 la $a0,gototheline syscall #print result li $v0,1 addi $a0,$v1,0 syscall li $v0,10 syscall ifeven: #print message if even la $a1,message1 syscall #call the function operation even to do math on the number entered by user jal operationeven ifodd: #print message if odd la $a2,message2 syscall #call method to do math on the number entered by user jal operationodd operationeven: #if even n/2 div $v1,$t3,2 # return value on $v1 jr $ra #go back to the main operationodd: #multiply by 3 mul $t1,$t3,3 #add 1 to the result of the multiplication add $v1, $t1,1 #return value on $v1 jr $ra #go back to the main

Answers: 1

continue

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