This time, if xyzfunc executes myint++, what happens to the copy of myint in the calling program?

a) its address is incremented by four.

b) it is incremented by one.

c) it doesn't change.

d) it doesn't change until the function returns.

a) Its address is incremented by four.

Explanation:

In cases of pointer when we pass them to a function the copy that is created in the function points to the same memory address to which the original pointer pointed.So on increasing it's value in the function will tell the pointer to move to the next integer location that is 4 bytes ahead hence the answer is option a.

solution:

this situation is called an ip conflict.

data from a server is sent in small bits called packets. in an ip conflict, some packets will end up in one computer while some other packets will end up in another computer.

so…overall none of the computers get the data as the original message or picture being sent by the server cannot be retrieved with only half the packets. so it will show up as an error.

thus the final answer is d.