Computers and Technology, 16.09.2019 21:00, nanda22

It launches a direct connection to that ip address and the desired port (like 80 for web connections) and awaits the server's response.

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Computers and Technology, 21.08.2019 01:10, alexvane78

This assignment requires you to develop two python programs. one is a client, the other is the server.stuck on a few different spots of this python assignmentserverthe server should “register” x procedures that the client will be able to call. it will then bind to the address “localhost” and port 8000. this is the address and port that the server will listen to for requests. note that if you have binding errors, you may use another port as your computer may have an application that is using 8000. most of the time, however, this will work. your server invocation must be in the following form: python server.py localhost 8000these procedures to be supported are as follows: name – returns the name of the server which is passed on the commandline during server – returns a list of procedures that the server supportsservertime – returns the current time at the server in 24 hour format. i.e. 13: 00: 01add(x,y) – returns the sum of x and ysub(x,y) – returns x – ymult(x,y) – returns x * ydiv(x,y) – returns x/yclientthe client is to connect to the server using the server’s address and the port that the server is listening on (see above). it then will exercise each of the supported procedures using the values 8 and 6 for the values x and y respectively. your client invocation must be in the following form: python client.py host_address host_port 8 6where host_address and host_port are the address and port that the server is listening on. if you are using a single computer for server and client computers just use “localhost” for the address and the port used above. the 8 and the 6 are the values for x and y.

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Engineering, 18.10.2019 19:00, GrainLeaf

Servers can be designed to limit the number of open connections. for example, a server may wish to have only n connections active at any time. as soon as n connections are established, the server will not handle more connections until at last one existing connection is closed. how would you use semaphores to limit the number of concurrent connections? assume that you have a function called () and one called which are called before and at the end of handling a connection. how would you add the necessary synchronization code to limit the number of concurrent connections to at most n?

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Engineering, 06.11.2019 22:31, leledaisy1994

Server x is running diablo ii services on port #4000. client a is running an application that uses port #450 to request an diablo ii tcp connection to server x. client b is running an application that uses port #455 to request an diablo ii tcp connection to server x. ip addresses: server x: 152.111.20.36 client a: 113.13.131.10 client b: 114.192.111.23 client b starts a second application (running at the same time as the first application) that uses the next incremental port number to request an diablo ii tcp connection to server x. the connection created for client b is identified by the sockets at the endpoints as follows: p address port number on client select ] [select ] on server [select ] select]

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Computers and Technology, 16.11.2019 01:31, sistersquad

Servers can be designed to limit the number of open connections. for example, a server may wish to have only n socket connections at any point in time. as soon as n connections are made, the server will not accept another incoming connection until an existing connection is released. explain how semaphores can be used by a server to limit the number of concurrect connections.

Answers: 2

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It launches a direct connection to that ip address and the desired port (like 80 for web connections...

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