Write a program that takes an integer n as a parameter and sums all of the multiples of 2 or 5 from 1 to n. for example, if n = 11, the result would be 2 + 4 + 5 + 6 + 8 + 10 = 35.

// here is code in c++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main() {

// variable

int num;

int tot_sum=0;

cout<<"enter a number: ";

// read the value of n

cin>>num;

// check the multiple of 2 or 5 from 1 to n

for(int x=1;x<=num;x++)

{

// if multiple of 2 or 5 then add them

   if(x%2==0 ||x%5==0)

   {

       tot_sum=tot_sum+x;

   }

}

// print the sum

cout<<"sum of multiple of 2 or 5 is:"<<tot_sum<<endl;

return 0;

}

Explanation:

Read the number "n" from user.Check every number from 1 to n, if it is a multiple of 2 or 5 then add them to "tot_sum".When the for loop end, "tot_sum" will have sum of all the number which are either multiple of 2 or 5.Print the sum.

Output:

enter a number:11

sum of multiple of 2 or 5 is:35

omg taking this same test i was stuck on the same question i was too lazy to read the book sadly i cant really give you an answer to this question too complex the answer will be in chapter 5 of the cay

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