Computers and Technology

There are n^1/2 copies of an element in the array c[1..n]. every other element of c occurs exactly once. if the randomized algorithm of finding the repeated element, which is introduced in class, is used to identify the repeated element of c, will the run time still be o~(logn)? if so, why? if not, what is the new run time?

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There are n^1/2 copies of an element in the array c[1..n]. every other element of c occurs exactly o...

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