Exercise 4.4.6: wait/signal vs wait/notify. info about a different version of a monitor, developed for the programming language mesa, replaces the primitive "signal" with "notify", which does not block the invoking process on the urgent queue but allows the process to finish the current function. as a result, a process is able to execute multiple "notify" statements before exiting a function. two processes, p1 and p2, call the function f() in the following monitor and since x < 0, both become blocked on c. a process p3 calls g() and notifies both p1 and p2 that x is now greater than 0. monitor m { x = -1 f() { if (x < 0) c. wait x = h(x) } g() { x = 1 c. notify c. notify } (a) what could go wrong with this code and yield incorrect results? (b) how could the program be modified to avoid the problem?