Write a console application that prompts the user to enter 3 integers and 3 doubles, then calculates and displays the sum, average, product, minimum and maximum.

Here is code in c++.

#include <bits/stdc++.h>

using namespace std;

int main()

{

   // integer array to store 3 int value

   int arr[3];

   // double array to store 3 double value

   double arr1[3];

   double sum=0;

   double avg;

   double product=1;

   double min=INT_MAX;

   double max=INT_MIN;

   cout<<"Enter 3 integer values:";

   //read 3 integer values

   for(int i=0;i<3;i++)

   {

       cin>>arr[i];

       // find total sum

       sum=sum+arr[i];

       // calculate product

       product=product*arr[i];

       // finding minimum value

       if(double(arr[i])<min)

       min=double(arr[i]);

       // finding maximum value

       if(double(arr[i])>max)

       max=double(arr[i]);

   }

   cout<<"Enter 3 double values:";

   //read 3 double values

   for(int i=0;i<3;i++)

   {

       cin>>arr1[i];

       // find total sum

       sum=sum+arr1[i];

       // calculate product

       product=product*arr1[i];

       // finding minimum value

       if(arr1[i]<min)

       min=arr1[i];

       // finding maximum value

       if(arr1[i]>max)

       max=arr1[i];

   }

   //calculate average of all 6 numbers

   avg=sum/6;

   // print the result

   cout<<"sum of all: "<<sum<<endl;

   cout<<"average of all: "<<avg<<endl;

   cout<<"Product of all: "<<product<<endl;

   cout<<"minimum of all: "<<min<<endl;

   cout<<"maximum of all: "<<max<<endl;

  return 0;

}

Explanation:

Create two  array "arr1" of int type to store 3 integer values and "arr2" of double type to store 3 double values.Calculate sum of all 6 numbers and find their average. After that calculate product of all the numbers.then find the minimum and maximum of all the values(in both integer and double).

Output:

Enter 3 integer values:5 2 10

Enter 3 double values:3.3 10.3 5.5

sum of all: 36.1

average of all: 6.01667

Product of all: 18694.5

minimum of all: 2

maximum of all: 10.3