What will be the contents of the ax and bx registers after the entire code is executed. (8086 microprocessors )
mov ax, 3432
mov bx, 1238
add bx, ax
aaa

The contents in ax and bx registers are as following:-

ax=3432

bx=4670

Explanation:

mov command in 8086 is an important command in 8086 microprocessors.It moves the data from the source to destination.

mov destination,source

add it adds the data to the destination with the content of destination.

add a,b means add b to a.

in operation mov ax,3432 we are moving 3432 to ax register similarly moving 1238 to bx.

Now adding ax to bx so the content of bx =1238+3432 that is 4670.

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answer(d) sequencing and iteration;