Anetwork with 10 bits remaining for the host portion will have how many usable host addresses?

2^10 = 1024 addresses

Explanation:

Each bit can be either 1 or 0, and this holds true for all 10 bits. So for every bit, we choose either a 0 or a 1 (2 choices), and then do so for the remaining bits. So we have 2 * 2 * 2 * ... * 2 (10 2's) choices for all 10 bits

solution:

the right option is a

to adding   a new row to a table we   have to do process last table cell and pressing tab.

this is the process to add new row in the cell:

* to add a row below the cell, click insert below in the rows and columns group.

thus this is the required right answer.