Sara is using her personal laptop (which is password protected) at a "hotspot" at a local cafe with wifi access. she is in the middle of placing an online order when friends arrive and she stops her work to visit. what is her best (and most convenient) way to protect the pii that she has already entered (she has only logged onto a site with her id and password and put some items in her basket for purchase)?

That i would call a dead end, since you can't know that it's always possible to immediately reconnect (server could be down, lines between you and the server could be down), and even if it was this would take some time slipping the packages out your wan in the meantime.the solution to this problem rather like satras says to block wan access for those hosts, and if policy routing is being used you need to use the soltion found by fastlanejb in this thread:   the link to the problem forum 

Public static int mystery(int a[], int x) {     int c = 0;     for(int i = 0; i < a.length; i++) {        if (a[i] == x) c++;     } return c; }the method counts how many times an integer shows up in an integer array.the c variable is declared in the method to keep track of how many times the certain value has shown up.the for-loop loops through the entire array.the line    if (a[i] == x) c++;   checks if each element of the array is equal to the inputted integer to check. for each number in the array that is equal to the inputted integer x, the c variable will be incremented by 1. otherwise it will do nothing.then c is returned at the end of the loop.for example, if we have, in the main method with the mystery method coded in the class:     int arraytest[] = {2, 23, 23, 23, 3};     int testme = 23;     int count = mystery(arraytest, testme);     system.out.println(count); then the print out will be    3 because there are three 23s in that array.

(1)correct answer is d.the others are just bad syntax.by using the keyword "new" and int[] together, you create a new integer array object in memory. whenever you want to create an object without using array literals, you must use new. (by array literals, i mean a line of declaration code like int[] x = {4,6}; where you literally specify an array without using new. an array literal can only be used in the same line as declaring the array.)(2)correct answer is c. it is the only choice that returns an array and properly takes in an array reference as an argument.choices a and b do not return an array; they respectively return void (nothing at all) and a primitive double, which is not a double array.choice d has invalid syntax. looking at it, it won't properly accept any array reference you pass into the method.(3)correct answer is a.x is already defined.choice b only returns an index of the array.also, in any other method, you wouldn't write the type next to the thing being returned. choices c and d are invalid.(4)correct answer is c.choice a only accepts one.choice b requires at least two numbers.choice d only takes in an integer array reference, not integers.(5) correct choice is d.by specifying that the first argument can take in any number of ints, java will assume everything you input into the method will be an integer.theoretically it will never reach that string argument, no matter how many commas you put. this is illegal; the java compiler will complain. i don't think it'll even recognize it as a method header.

Ufudhdududhhcjcjcjxjxjjd