Write a program that lets the user play the game of rock, paper, scissors against the computer. the program should work as follows. 1. when the program begins, a random number in the range of 1 through 3 is generated. if the number is 1, then the computer has chosen rock. if the number is 2, then the computer has chosen paper. if the number is 3, then the computer has chosen scissors. (don’t display the computer’s choice yet.) 2. the user enters his or her choice of “rock”, “paper”, or “scissors” at the keyboard. (you can use a menu if you prefer.) 3. the computer’s choice is displayed. 4. a winner is selected according to the following rules: • if one player chooses rock and the other player chooses scissors, then rock wins. (the rock breaks the scissors.) • if one player chooses scissors and the other player chooses paper, then scissors wins. (scissors cuts paper.) • if one player chooses paper and the other player chooses rock, then paper wins. (paper wraps rock.) • if both players make the same choice, the game must be played again to determine the winner. be sure to divide the program into functions that perform each major task. include the code and the console output from running your program with test inputs in your report.

#include <iostream>

#include <ctime>

#include <conio.h>

using namespace std;

bool player_won (int player, int computer)

{

   switch (player)

   {

   case 1:

       if (computer==2)

           return false;

       else return true;

   case 2:

       if (computer==3)

           return false;

       else return true;

   case 3:

       if (computer==1)

           return false;

       else return true;

   }

}

main ()

{

   cout<<"Rock, paper scissors by TheMaster999"<<endl;

   srand (time(NULL));

   while (true)

   {

       int computer=rand()%3+1;

       int player;

       cout<<"If u choose rock type 1, if u choose paper type 2, if u choose scissors type 3"<<endl;

       cin>>player;

       if (player==computer)

           cout<<"Draw, play again"<<endl;

       else if (player_won(player,computer))

       {

           cout<<"Congratulations, you won!"<<endl;

           break;

       }

       else

       {

           cout<<"You lost :("<<endl;

           break;

       }

   }

   cout<<"Thank you, for playing my game"<<endl;

   getch();

   return 0;

}

the correct answer is: a.)it is never appropriate to use acronyms and emoticons in business communication.

only #2 represents an object at rest on a table.

in #1, there is no normal force due to the table; the object is accelerating downward.

in #3, the vertical forces are not balanced; the object is accelerating downward.

in #4, neither the vertical nor the horizontal forces are balanced. the object is accelerating upwards and to the right.