Computers and Technology, 13.01.2020 05:31, kelly3215

500905.0130001110133131131110313130 111500905.0

name of this dessert

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answered: Guest

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answered: Guest

Answer:

the correct option is (d) vin label

explanation:

vin stands for vehicle information number. this is a thin metallic plate attached to the engine of the vehicle and it includes all the important information which are related to the vehicle. it also provides the information whether the vehicle has been stolen or not because the replacement and alternation of vin number creates difference in the exact number printed on the vin and carved on the engine.

answered: Guest

Ndnekfnekfnwodjefjdj5

answered: Guest

The answer is c. 36======analyzing the for-loop, we see that the control variable, k, starts at 0 and increments by after every loop iteration. the condition $\texttt{k\ \textless \ =7}$ tells us that the loop will stop when k is above 7; in this case, when k is 8.0 1 2 3 4 5 6 7 are the values for k that will be used. each number is for each iteration; therefore, the for-loop will have 8 iterations in total.the code inside the loop itself goes like this: 1st iteration (k=0)starting with sum=0, val=1 $\texttt{sum += val; }$ means that add $\texttt{val}$ to $\texttt{sum}$ .since sum is 0 and val is 1, 0 + 1 = 1. the new value of sum is 1. $\texttt{val++; }$ means to increment $\texttt{val}$ by 1.since val is 1, the new value of val of 2.end of iteration with k=0; k is increased by one to become k=12nd iteration (k=1)starting with sum=1, val=2 $\texttt{sum += val; } \iff \texttt{sum = 1 + 2}$ ======let us establish a pattern. this is moreso logic than programming: we can rewrite $\texttt{sum = 1 + 2}$ so that we have the elements from the previous iteration. the 1 came from 0 + 1 before. so we can write it as $\texttt{sum = 0 + 1 + 2}$ .and if we did the third iteration, by the end, sum would look like $\texttt{sum = 0 + 1 + 2 + 3}$ notice how the number of plus signs is equal to the iteration you are on (which is just k+1), and what is being added is increasing by one each time. for example, the third iteration (k=2) ends up with $\texttt{sum = 0 + 1 + 2 + 3}$ with 3 plus signs.the second iteration (k=1) ends up with $\texttt{sum = 0 + 1 + 2}$ with two plus signs.the first iteration (k=0) ends up with $\texttt{sum = 0 + 1}$ with one plus sign.this is a pattern. the nth iteration will have n plus signs.since we established before that there are 8 iterations of this loop in total, the value of sum at k=7 (the 8th and last iteration) will have sum with 8 plus signs. $\begin{aligned} \texttt{sum} & = \texttt{0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 } \\ & = \texttt{3 + 3 + 4 + 5 + 6 + 7 + 8 } \\ & = \texttt{6 + 4 + 5 + 6 + 7 + 8 } \\ & = \texttt{10 + 5 + 6 + 7 + 8 } \\ & = \texttt{15 + 6 + 7 + 8 } \\ & = \texttt{21 + 7 + 8 } \\ & = \texttt{28 + 8 } \\ & = \texttt{36} \end{aligned}$ so the value of sum at the end of the loop is 36.