Computers and Technology
Computers and Technology, 15.10.2019 03:30, lovevanna

In preparing his persuasive presentation, reza should most likely focus on clearly presenting his

unique ideas.

expert knowledge.

point of view.

visual aids.

answer
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Computers and Technology, 22.06.2019 13:00, jairus34
We as humans write math expression in infix notation, e. g. 5 + 2 (the operators are written in-between the operands). in a computer’s language, however, it is preferred to have the operators on the right side of the operands, i. e. 5 2 +. for more complex expressions that include parenthesis and multiple operators, a compiler has to convert the expression into postfix first and then evaluate the resulting postfix. write a program that takes an “infix” expression as input, uses stacks to convert it into postfix expression, and finally evaluates it. it must support the following operations: + - / * ^ % (example infix expression: (7 - 3) / (2 + 2)postfix expression: 7 3 - 2 2 + /result: 1guidelines: 1. you will need to use stacks in three placesa. one for the parenthesis check [char stack]b. one during infix to postfix [char stack]c. one during evaluation [int stack]for a and b above, you can use same array and same push, pop method as both ofthem are char. but for evaluation you have int stack and you might consider to createanother push pop method to handle it. maybe push_int, pop_int, etc. or find otherstrategy to utilize existing push pop method2. you can create a function for obtaining operator priority. that function should take anoperator as input and return its priority as an integer. this function will you a lot andreduce repeated code3. during evaluation you will need to convert char into integer. example for single digit: char c = '5'; int x = c - '0';
Answers: 2
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Computers and Technology, 23.06.2019 12:00, anamatiascamaja
If you embed a word table into powerpoint, what happens when you make edits to the embedded data? a. edits made to embedded data change the data in the source file; however, edits made to the source file will not be reflected in the embedded data. b. edits made to embedded data will change the data in the source file, and edits made to the source file will be reflected in the embedded data. c. edits made to embedded data don't change the data in the source file, nor will edits made to the source file be reflected in the embedded data. d. edits made to embedded data don't change the data in the source file; however, edits made to the source file will be reflected in the embedded data.
Answers: 1
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Computers and Technology, 23.06.2019 18:30, bsept1018
Report all segments of identity by descent longer than 20 polymorphisms between pairs of individuals in the following cohort of 15 individuals across 49 polymorphisms: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 numeric input 2 points possible (graded) you have 2 attempts to complete the assignment below. for example if the sequence is "bcd", which occurs in "abcdef" , the starting point would be 2 (b), and the finishing point would be 4(d). individuals 7,10 between positions
Answers: 1
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Computers and Technology, 23.06.2019 19:00, brittneyrenae7338
This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words. size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words. size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }
Answers: 1
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In preparing his persuasive presentation, reza should most likely focus on clearly presenting his

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