Create a logic array qualifyingindex with true for any location where the runner is male with a running time less than 8.2. row array runnergenders indicate if a runner if male (m) or female (

f. row array runnertimes indicates the corresponding runner's time.

qualifyingIndex = (runnerGenders == 'M' & (runnerTimes < 8.2));

Explanation:

Because the problem specifies "logic array", one of the logical operators (i.e. &, |, ~) will be used. Because it asks for the runner to be male AND have a time less than 8.2, those are two the factors.

To break down the parts:

runnerGenders == 'M' searches the ['M', 'F', 'M', 'M', 'F'] array for all genders that are equal to male.

runnerTimes < 8.2 searches the [8.5, 9, 7.7, 7.9, 7.2] array for all times less than 8.2

By putting them together and using the logical operator & to represent "and", you have your answer of qualifyingIndex = (runnerGenders == 'M' & (runnerTimes < 8.2));

Note for future viewers: The OP did not include a screenshot of the original problem, but I had the same question on my MATLAB homework so I could easily reference what the array values were.

its called a apple tv

explanation:

solution:

the auto-correct option of the auto-correct tool enables you to add and delete words that do not follow abbreviation rules because:

it is a feature that allows outlook to correct common spelling and typing errors and to replace characters with symbols. we can also can use auto-correct as a shortcut, which means we can type a small string of characters and have those characters replaced by a longer string.